-[6z-(11z+2)]=2+(4z+0)

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Solution for -[6z-(11z+2)]=2+(4z+0) equation:


Simplifying
-1[6z + -1(11z + 2)] = 2 + (4z + 0)

Reorder the terms:
-1[6z + -1(2 + 11z)] = 2 + (4z + 0)
-1[6z + (2 * -1 + 11z * -1)] = 2 + (4z + 0)
-1[6z + (-2 + -11z)] = 2 + (4z + 0)

Reorder the terms:
-1[-2 + 6z + -11z] = 2 + (4z + 0)

Combine like terms: 6z + -11z = -5z
-1[-2 + -5z] = 2 + (4z + 0)
[-2 * -1 + -5z * -1] = 2 + (4z + 0)
[2 + 5z] = 2 + (4z + 0)

Reorder the terms:
2 + 5z = 2 + (0 + 4z)
Remove the zero:
2 + 5z = 2 + (4z)
2 + 5z = 2 + (4z)

Add '-2' to each side of the equation.
2 + -2 + 5z = 2 + -2 + (4z)

Combine like terms: 2 + -2 = 0
0 + 5z = 2 + -2 + (4z)
5z = 2 + -2 + (4z)

Combine like terms: 2 + -2 = 0
5z = 0 + (4z)
5z = (4z)

Solving
5z = (4z)

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '(-4z)' to each side of the equation.
5z + (-4z) = (4z) + (-4z)

Combine like terms: 5z + (-4z) = 1z
1z = (4z) + (-4z)

Combine like terms: (4z) + (-4z) = 0
1z = 0

Divide each side by '1'.
z = 0

Simplifying
z = 0

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